BTU Stayman 2

BTU Stayman is characterized by including invitations of 5= spades. All its variants are:

  • Weak: T/O with short clubs (Garbage Stayman)
  • Invitational: 4–5 or 4= (BTU)
  • Game-forcing: 4= or 4=
1NT-2-BTU STAY
2!2–3, 2–3
24=, 2–3
24=, 2–3
2NT!MIN, 44(xx)
3!MAX, 44(xx)

1NT-2-2

  • Smolen at both levels takes care of spade invitation.
  • Second responses above 3NT remain the same, assuming misfit.
1NT-2-2-NEG
2!TRF INV, 5+
2!NF INV Smolen, 4=, 5+
2NTNAT INV
3FG, 5+
3FG, 5+
3!FG, Smolen TRF, 54(xx)
3!FG, Smolen TRF, 45(xx)
4!Gerber BW
4!Texas TRF, 6+, 4=
4!Texas TRF, 6+, 4=
4!F QUANT
4NTQUANT INV to 6NT
5NTQUANT INV to 7NT
1NT-2; 2-2-INV, 5+
2MIN
2NTINV, 2=
3!INV, xx in this suit, 3=
3INV, 3=

1NT-2-2

  • BTU QUANT scheme remains, assuming misfit.
  • 3 is a generic fit S/T, so 4NT is QUANT instead of RKCB.
1NT-2-2-4=, 2–3
2INV, 5+
2NTINV, 0–3, 4=
3FG, 5+, 0–3, 4=
3FG, 5+, 0–3, 4=
3INV, 4+
3!S/T, 4+
4!S/T SPL, 0–1#, 4+
4!F QUANT
4NTQUANT INV to 6NT
5NTQUANT INV to 7NT
1NT-2; 2-2-INV, 5+
2NTINV, 2=
3!INV, xx in this suit, 3=
3INV, 3=

1NT-2-2

  • Only standard QUANT scheme remains. Now 4 is S/O.
  • 3 is a generic fit S/T, so 4NT is QUANT instead of RKCB.
1NT-2-2-4=, 2–3
2NTINV, 0–3, 4=
3FG, 5+, 0–3, 4=
3FG, 5+, 0–3, 4=
3!S/T, 4+
3INV, 4+
4!S/T SPL, 0–1#, 4+
4S/O, 4+
4NTQUANT INV to 6NT
5NTQUANT INV to 7NT